摘要: task4 #include <stdio.h> int main() { int count = 0; char c; FILE *fp ; fp = fopen("data4.txt", "r"); if (fp ==NULL) { printf("fail to open the file\n 阅读全文
posted @ 2024-06-18 17:32 孙诗悦 阅读(21) 评论(0) 推荐(0)