摘要:
// 八皇后int ANS[8], y[8]; bool xie1[16], xie2[16]; int dfs(int line) { int ans = 0; if (line == 8) return 1; for (int i = 0 ; i < 8 ; i ++){ if (y[i] || xie1[line - i + 7] || xie2[l... 阅读全文
posted @ 2017-08-28 10:20
默默无语敲代码
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