摘要:
#include using namespace std; void merge(int a[], int p, int q, int r) { int n1 = q - p + 1; int n2 = r - q; int* L = new int[n1 + 2]; int* R = new int[n2 + 2]; L[n1+1]=0x7fffffff; R[n2+1]=0x7... 阅读全文
posted @ 2017-05-22 23:36
好吧,就是菜菜
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