摘要:
1. Do not mess it up with number of islands. Each path extends only choose one.
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posted @ 2016-07-02 05:13
keepshuatishuati
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1. Use the condition : he/she knows no one. So you can get candidate by filtering out whether a candidate knows somebody. 2. Use the condition : all o
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posted @ 2016-07-02 03:10
keepshuatishuati
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Code is simple. But the logic is: 1. start search from [1, n], when you find a number in nums that less than missed, add it to missed. Then you can fo
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posted @ 2016-07-01 16:09
keepshuatishuati
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1. This is counting leaves and trees method. It should starting from end, which gareentee the leaves is larger than tree. A nice regex work:
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posted @ 2016-07-01 15:56
keepshuatishuati
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1 public class Solution { 2 public List findItinerary(String[][] tickets) { 3 List result = new ArrayList(); 4 if (tickets.length == 0 || tickets[0].length == 0) { 5 ...
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posted @ 2016-07-01 15:31
keepshuatishuati
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1. j can reach word[i].length() since it can form an empty string; 2. to aviod duplication ( empty string can cause two found for a pair ,ex [abcd, db
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posted @ 2016-07-01 15:12
keepshuatishuati
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1. put element do not forget to + 1 2. do not forget left move left++.
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posted @ 2016-07-01 14:46
keepshuatishuati
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1 /** 2 * // This is the interface that allows for creating nested lists. 3 * // You should not implement it, or speculate about its implementation 4 * public interface NestedInteger { 5 * ...
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posted @ 2016-07-01 05:40
keepshuatishuati
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1. Be careful with index.
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posted @ 2016-07-01 05:21
keepshuatishuati
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1. One thing need to be notice that if player put to wrong place...
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posted @ 2016-07-01 05:01
keepshuatishuati
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