m(n) = 1/2 + 2/3 + ... +n/n+1 def sljisuan(): s = 0 n = int(input("请输入需要求和的数:")) for i in range(1,n+1): s += i/(i+1) print("前{0}项和为{1}".format(n,s)) s Read More
def reverse(): number = eval(input("请输入一个整数")) a = number // 10000 b = (number % 10000) // 1000 c = (number % 1000) // 100 d = (number % 100) // 10 f Read More