11 2015 档案

摘要:1. always(posedge CLOCK) 2. case(i) 3. 4. 0: 5. if(C1 == 8) begin C1 <= 4’d0; i <= i + 1’b1; end 6. else begin ... 阅读全文

posted @ 2015-11-04 16:01 s010101 阅读(409) 评论(0) 推荐(0)

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