2013年2月25日
记一个生成罗马数字的代码
摘要： 1 int f[15]={1,4,5,9,10,40,50,90,100,400,500,900,1000},num[10]; 2 int co[15][10]={{1},{1,1},{0,1},{1,0,1},{0,0,1},{0,0,1,1},{0,0,0,1},{0,0,1,0,1},{0,0,0,0,1},{0,0,0,0,1,1},{0,0,0,0,0,1},{0,0,0,0,1,0,1},{0,0,0,0,0,0,1}}; 3 char ss[10] = {'I','V','X','L','C', 阅读全文
posted @ 2013-02-25 10:33 _雨 阅读(318) 评论(0) 推荐(0)