10 2023 档案

摘要：'''rsa3-->c1,c2,e1,e2 公共模数攻击'''from Crypto.Util.number import *import gmpy2'''c1 = pow(m, e1, N)c2 = pow(m, e2, N)''''''m = pow(c1, d1, N)m = pow(c2, 阅读全文

摘要：已知e,n,c,p,q(但是n?=p*q)例如：'''n=p*p*p*q*q''' import gmpy2from Crypto.Util.number import *e =q = p = c = n = p*p*p*q*q'''当n分解类似p*p*pphi = p*p*p-p*p'''phi 阅读全文

摘要：已知c,e,n,dp 求m（dp=d%(p-1)）import gmpy2from Crypto.Util.number import *n =dp =c =e = tmp = e * dp -1#根据联立条件有: e*dp = 1 + k(p-1)，故求解p的式子为：(p-1) = (e*dp-1 阅读全文

摘要：已知c,e,n 求m(n能分解p,q) import gmpy2 from Crypto.Util.number import * c = e = n = n = p*q #yafu factordb.com分解n p = q = phi = (p-1)*(q-1) d = gmpy2.invert 阅读全文