摘要: 1.检测是否为乱码 public static boolean isMessyCode(String strName) { Pattern p = Pattern.compile("\\s*|\t*|\r*|\n*"); Matcher m = p.matcher(strName); String 阅读全文
posted @ 2016-02-02 11:40 浪荡小新 阅读(2219) 评论(1) 推荐(1)