1.输入一个年份,判断是不是闰年(能被4整除但不能被100整除,或者能被400整除)
import java.util.Scanner;
public class first {
public static void main(String[] args) {
System.out.println("请输入一个年份");
Scanner sc = new Scanner(System.in);
int year = sc.nextInt();
if ((year % 4 == 0 && year % 100 != 00) || (year % 400 == 0)) {
System.out.println(year + "是一个闰年");
} else {
System.out.println(year + "是一个平年");
}
}
}
2.输入一个4位会员卡号,如果百位数字是3的倍数,就输出是幸运会员,否则就输出不是.
import java.util.Scanner;
public class first {
public static void main(String[] args) {
System.out.println("请输入会员卡号");
Scanner sc = new Scanner(System.in);
int id = sc.nextInt();
if (id % 1000 / 100 % 3 == 0) {
System.out.println("幸运会员");
} else {
System.out.println("不是");
}
}
}
3.已知函数,输入x的值,输出对应的y的值.
x + 3 ( x > 0 )
y = 0 ( x = 0 )
x*2 –1 ( x < 0 )
import java.util.Scanner;
public class first {
public static void main(String[] args) {
System.out.println("请输入x的值");
Scanner sc = new Scanner(System.in);
int x = sc.nextInt();
int y;
if (x>0) {
y=x+3;
System.out.println("y的值为:"+y);
} else if (x==0){
y=0;
System.out.println("y的值为:"+y);
}else if (x<0){
y=x*2-1;
System.out.println("y的值为:"+y);
}
}
}
4.输入三个数,判断能否构成三角形(任意两边之和大于第三边)
import java.util.Scanner;
public class first {
public static void main(String[] args) {
System.out.println("三角形的三个边长");
Scanner sc = new Scanner(System.in);
int a = sc.nextInt();
int b = sc.nextInt();
int c = sc.nextInt();
if ((a + b) > c && (a + c) > b && (b + c) > a) {
System.out.println("可以构成三角形");
}
System.out.println("不可以构成三角型");
}
}
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