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AVG()和SUM()函数 1 /*求平均数*/ 2 SELECT AVG(分数) AS 平均分 FROM user_03 3 WHERE id='04183001' 4 /*求总和*/ 5 SELECT SUM(分数) AS 总分 FROM user_03 6 WHERE id='04183001 阅读全文
posted @ 2020-07-17 15:49
ryk72835
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交叉关联 user_00 user_02 1 /*交叉关联*/ 2 SELECT * FROM user_00 a 3 INNER JOIN user_02 b 4 ON a.id=b.id 左关联查询 1 SELECT * FROM user_00 a 2 LEFT JOIN user_02 b 阅读全文
posted @ 2020-07-17 15:07
ryk72835
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返回结果排序 1 SELECT * FROM user_02 2 ORDER BY id ASC /*升序*/ 1 SELECT * FROM user_02 2 ORDER BY id DESC /*降序*/ 再次查询 1 SELECT * FROM user_02 对两个或两个以上的数据进行排序 阅读全文
posted @ 2020-07-17 13:47
ryk72835
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EXISTS子查询 user_00 user_01 1 SELECT a.id,a.name,a.age FROM user_00 a 2 WHERE EXISTS(SELECT * FROM user_01 b WHERE a.id=b.id) 阅读全文
posted @ 2020-07-17 10:45
ryk72835
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