摘要: 1.continue 1 for ((i=1;i<10;i++)) 2 do 3 if [ $i -eq 5 ];then 4 continue 5 fi 6 7 echo $i 8 9 done # ./continue.sh12346789 2.break 1 for ((i=1;i<10;i+ 阅读全文
posted @ 2020-02-10 15:57 wilson'blog 阅读(142) 评论(0) 推荐(0)