餐盘模拟 数据结构及其描述

如何模拟向餐盘中添加物品

po上来证明我来过

package ObjectWash;

public class Object {
	String name;
	int WashingCost;
	int TransCost;
	int length, width;

	Object(String mingcheng, int xishuanshijian, int zhuanyishijian, int chang, int kuan) {
		this.name = mingcheng;
		this.WashingCost = xishuanshijian;
		this.TransCost = zhuanyishijian;
		this.length = chang;
		this.width = kuan;
	}

	public int[][] CalSize(int length, int width) {
		int[][] array = new int[length][width];
		for (int i = 0; i <length ; i++)
			for (int j = 0; j <width ; j++) {
				array[i][j] = 1;
			}
		return array;
	}
	void ObjectRotate(Object a) {//将待过机物品旋转90度
		int Otemp=a.length;
		a.length=a.width;
		a.width=Otemp;
		System.out.println(a.name+"旋转后样式如下:\n");
		a.showObj(a);
	}
	void showObj(Object a) {
		int[][] arr=a.CalSize(length, width);
		System.out.println(a.name+"的样式为:");
		for(int i=0;i<length;i++) {
			
			for(int j=0;j<width;j++) {
				System.out.print(arr[i][j]+" ");
			}
			System.out.println(" ");
		}
		System.out.println(" ");
	}
}

package ObjectWash;

public class Dish {
	char DishNum;
	int[][] DishSpace = new int[6][6];// 过机盘的空间为6*6
	Object[] waitList = new Object[20];

	Dish(char Name) {
		this.DishNum = Name;
	}

	int[] CheckIn(Dish a, Object b) {// 遍历过机盘,返回第一个可以插入的位置索引
		int[] set = new int[2];
		all: for (int i = 0; i < 6; i++) {
			if (5 - i < b.width) {
				continue;
			}
			a: for (int j = 0; j < 6; j++) {
				if (5 - j < b.length) {
					continue;
				}
				if (a.DishSpace[i][j] == 0) {
					set[0] = i;
					set[1] = j;
				}
				int area = 0;
				for (int k = set[0]; k < b.length; k++) {
					for (int m = set[1]; m < b.width; m++) {
						if (a.DishSpace[k][m] == 0) {
							area += 1;
						} else {
							continue a;
						}
					}
				}
				if (area == (b.length * b.width)) {
					break all;
				}
			}
		}
		return set;
	}

	void showDish(Dish a) {// 展示过机盘
		System.out.print("过机盘" + a.DishNum + "的状态为:");
		for (int i = 0; i < 6; i++) {
			System.out.println(" ");
			for (int j = 0; j < 6; j++) {
				System.out.print(a.DishSpace[i][j] + " ");
			}
		}
		System.out.println(" ");
	}

	boolean CompareArea(Dish a, Object b) {// 比较过机盘空闲空间和物品体积,能装下为真
		int area = 0;
		for (int i = 0; i < 6; i++) {
			for (int j = 0; j < 6; j++) {
				if (a.DishSpace[i][j] == 0) {
					area += 1;
				}
			}
		}
		if (area < (b.length * b.width)) {
			return false;
		} else {
			return true;
		}
	}

	void inDish(Dish a, Object b) {
		int x=0;
		int y=0;
		a: for (int i = 0; i < 6 - b.length; i++) {
			b: for (int j = 0; j < 6 - b.width; j++) {
				if (a.DishSpace[i][j] == 1) {
					continue b;
				} else {
					c: for (int k = i; k < 6 - b.length; k++) {
						d: for (int m = j; m < 6 - b.width; m++) {
							if (a.DishSpace[k][m] == 1) {
								continue b;
							}
						}
					}
				}
				x=i;
				y=j;
				break a;
			}
		}
		for(int i=x;i<b.length+x;i++) {
			for(int j=y;j<b.width+y;j++) {
				a.DishSpace[i][j]=1;
			}
		}
		System.out.println(b.name+"插入过机盘:"+a.DishNum+"成功!");
		a.showDish(a);
	}

	boolean judge(Dish a, Object b, int i, int j) {

	}
}

package ObjectWash;

public class MainTest {
	public static void main(String[] args) {
		Dish a=new Dish('B');
		Object o1=new Object("粉盒",20,50,2,1);
		Object o2=new Object("原子弹",0,0,50,60);
		Object o3=new Object("保时捷",0,0,5,2);
		
		o1.showObj(o1);
		o3.showObj(o3);
		a.inDish(a,o3);
		a.inDish(a, o1);
		o1.ObjectRotate(o1);
		a.inDish(a, o1);
	}

}

posted @ 2019-10-22 22:28  ExplodedVegetable  阅读(146)  评论(0编辑  收藏  举报