摘要: 如下的代码: button2.Dock = DockStyle.Top; button1.SendToBack(); button1.Dock = DockStyle.Top; button3.Dock = DockStyle.Bottom; 运行后,3个button的顺序始终为: button1 阅读全文
posted @ 2017-12-28 10:02 笑笑小白 阅读(1096) 评论(0) 推荐(0)