摘要: (1)将指定的位置设为1value = value | ( 1 << bit_number) value |= 1 << bit_number(2)将指定的位置清空value = value & ~( 1 << bit_number) value &= ~( 1 << bit_number) (3) 阅读全文
posted @ 2016-05-25 18:30 hbg-rohens 阅读(189) 评论(0) 推荐(0)