2018年5月23日
查询SYS_ORG_TB树的层级
摘要： WITH N(SYS_ORG_ID,SYS_ORG_NAME,LEVEL) AS( SELECT SYS_ORG_ID,SYS_ORG_NAME,1 AS LEVEL FROM SYS_ORG_TB WHERE SYS_ORG_UPID IS NULL UNION ALL SELECT T2.SYS_ORG_ID,T2.SYS_ORG_NAME, (T1.LEVEL + 1) AS LEVEL ... 阅读全文
posted @ 2018-05-23 10:11 _revolution 阅读(281) 评论(0) 推荐(0)