摘要:
1 void merge(int v[], int b, int n) { 2 int i = 0; 3 int j = b; 4 int *temp = new int[n]; 5 for (int k = 0; k = b) { 7 temp[k] = v[j++]; 8 continue; 9 ... 阅读全文
posted @ 2019-05-26 22:30
Ren.Yu
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1 void selection_sort(int v[], int n) { 2 for (int i = 0; i < n - 1; i++) { 3 int k = i; 4 for (int j = i; j < n; j++) { 5 if (v[j] < v[k]) { 6 k... 阅读全文
posted @ 2019-05-26 17:50
Ren.Yu
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1 void insertion_sort(int v[], int n) { 2 for (int i = 1; i 0; j--) { 6 if (v[j - 1] > k) { 7 v[j] = v[j - 1]; 8 } else { 9 break; 1... 阅读全文
posted @ 2019-05-26 16:06
Ren.Yu
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