BZOJ1085 [SCOI2005]骑士精神

搜索。。。还要A*。。。不会呢。。。

Orz 这个blog吧：iwtwiioi

 

 

 1 /**************************************************************
 2     Problem: 1085
 3     User: rausen
 4     Language: C++
 5     Result: Accepted
 6     Time:876 ms
 7     Memory:804 kb
 8 ****************************************************************/
 9  
10 #include <cstdio>
11 #include <algorithm>
12  
13 using namespace std;
14 const int dx[8] = {1, 2, 2, 1, -1, -2, -2, -1};
15 const int dy[8] = {2, 1, -1, -2, -2, -1, 1, 2};
16 const int last[6][6] = {
17 {0, 0, 0, 0, 0, 0},
18 {0, 1, 1, 1, 1, 1},
19 {0, 0, 1, 1, 1, 1},
20 {0, 0, 0, 2, 1, 1},
21 {0, 0, 0, 0, 0, 1},
22 {0, 0, 0, 0, 0, 0}};
23  
24 int s[6][6], ans, have_ans, X, Y;
25  
26 inline bool check(){
27     int i, j;
28     for (i = 1; i <= 5; ++i)
29         for (j = 1; j <= 5; ++j)
30             if (s[i][j] != last[i][j]) return 0;
31     return 1;
32 }
33  
34 inline bool f(const int &g){
35     int h = 0, i, j;
36     for (i = 1; i <= 5; ++i)
37         for (j = 1; j <= 5; ++j)
38             if (s[i][j] != last[i][j] && (++h) + g > ans) return 0;
39     return 1;
40 }
41  
42 void dfs(const int &x, const int &y, const int &g){
43     if (g == ans){
44         if (check()) have_ans = 1;
45         return;
46     }
47     if (have_ans) return;
48     int i, X, Y;
49     for (i = 0; i < 8; ++i){
50         X = x + dx[i], Y = y + dy[i];
51         if (X < 1 || Y < 1 || X > 5 || Y > 5) continue;
52         swap(s[x][y], s[X][Y]);
53         if (f(g)) dfs(X, Y, g + 1);
54         swap(s[x][y], s[X][Y]);
55     }
56 }
57  
58 int main(){
59     int T, i, j;
60     scanf("%d", &T);
61     char ch;
62     while (T--){
63         for (i = 1; i <= 5; ++i)
64             for (j = 1; j <= 5; ++j){
65                 ch = getchar();
66                 while (ch != '*' && ch != '0' && ch != '1')
67                     ch = getchar();
68                 if (ch == '*')
69                     s[i][j] = 2, X = i, Y = j;
70                 else s[i][j] = ch - '0';
71             }
72         if (check()){
73             printf("0\n");
74             continue;
75         }
76         have_ans = 0;
77         for (ans = 1; ans <= 15; ++ans){
78             dfs(X, Y, 0);
79             if (have_ans) break;
80         }
81         if (have_ans) printf("%d\n", ans);
82         else printf("-1\n");
83     }
84     return 0;
85 }
View Code

 

posted on 2014-10-27 18:23  Xs酱~  阅读(173)  评论(0)  编辑  收藏  举报