摘要:
简单题View Code #include <iostream>#include <cstdio>#include <cstdlib>#include <cstring>using namespace std;#define pi 3.14159bool reachable(int x, int y, int z, int &ans){ if (360 - z < z) z = 360 - z; if (z == 0) { ans = y; return true; } double dist = 2 * pi * x *... 阅读全文
posted @ 2013-03-12 13:15
undefined2024
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