摘要: 简单题,随便找一条棱,平均分成n份即可。View Code #include <iostream>#include <cstdlib>#include <cstdio>#include <cstring>using namespace std;int main(){ //freopen("t.txt", "r", stdin); int x, y, z, n; scanf("%d%d%d%d", &x, &y, &z, &n); for (int i = 阅读全文
posted @ 2012-11-17 11:06 undefined2024 阅读(162) 评论(0) 推荐(0)