poj3090

简单题

View Code
#include <iostream>
#include
<cstdlib>
#include
<cstring>
#include
<cstdio>
using namespace std;

#define maxn 1005

int n;
int f[maxn][maxn];

int gcd(int x, int y)
{
if (!x || !y)
return x > y ? x : y;
for (int t; t = x % y; x = y, y = t)
;
return y;
}

int main()
{
//freopen("t.txt", "r", stdin);
for (int i = 1; i <= 1000; i++)
for (int j = 1; j <= 1000; j++)
if (gcd(i, j) == 1)
f[i][j]
= f[i][j - 1] + f[i - 1][j] - f[i - 1][j - 1] + 1;
else
f[i][j]
= f[i][j - 1] + f[i - 1][j] - f[i - 1][j - 1];
int t;
scanf(
"%d", &t);
for (int i = 0; i < t; i++)
{
scanf(
"%d", &n);
printf(
"%d %d %d\n", i + 1, n, f[n][n] + 2);
}
return 0;
}
posted @ 2011-09-15 18:38  金海峰  阅读(184)  评论(0编辑  收藏  举报