实验4

实验5

task5.cpp

#include <iostream>
#include "vectorInt.hpp"
void test() {
    using namespace std;
    int n;
    cin >> n;
    vectorInt x1(n);
    for (auto i = 0; i < n; ++i)
        x1.at(i) = i * i;
    output(x1);
    vectorInt x2(n, 42);
    vectorInt x3(x2);
    output(x2);
    output(x3);
    x2.at(0) = 77;
    output(x2);
    output(x3);
}
int main() {
    test();
}

vectorInt.hpp

#pragma once
#include <iostream>
using namespace std;
class vectorInt
{
public:
    vectorInt(int n)
    {
        size = n;
        cout << "constructor 1 called.\n";
        data = new int[n];
        for (int i = 0; i < n; i++)
            data[i] = i;
    }
    vectorInt(int n, int value)
    {
        size = n;
        cout << "constructor 2 called.\n";
        data = new int[n];
        int i;
        for (i = 0; i < n; i++)
            data[i] = value;
    }
    vectorInt(vectorInt &x0)
    {
        cout << "copy constructor called.\n";
        int i = 0, n = 0;
        n=x0.size;
        size = n;
        data = new int[n];
        for (i = 0; i < n; i++)
            data[i] = x0.data[i];
    }
    ~vectorInt()
    {
        cout << "destructor called." << endl;
    }
    int &at(int i) const;
    int get_size(vectorInt x0) const;
    friend int output(vectorInt &x0);
private:
    int *data;
    int size;
    
};
int &vectorInt:: at(int i)const
{
    return data[i];
}
int vectorInt::get_size(vectorInt x0 )const
{
    return x0.size;
}
int output(vectorInt &x0)
{
    int i = 0;
    for (; i < x0.size; i++)
        cout << x0.data[i] << " ";
    cout << endl;
    return 0;
}

结果

实验6

 matrix.hpp

#pragma once
#include <iostream>
using std::cout;
using std::endl;
class Matrix {
public:
    Matrix(int n)// 构造函数，构造一个n*n的矩阵
    {
        p = new double[n * n];
        lines = n;
        cols = n;
    }
    Matrix(int n, int m)// 构造函数，构造一个n*m的矩阵
    {
        p = new double[n * m];
        lines = n;
        cols = m;
    }
    Matrix(const Matrix& X)// 复制构造函数，使用已有的矩阵X构造
    {
        p = new double[X.lines*X.cols];
        lines = X.lines;
        cols = X.cols;
        for (int obj=0; obj < X.lines * X.cols; obj++)
            p[obj] = X.p[obj];
    }
    ~Matrix() {} //析构函数
    void set(const double* pvalue) // 用pvalue指向的连续内存块数据按行为矩阵赋值
    {
        for (int i = 0; i < lines * cols; i++)
            p[i] = pvalue[i];
    }
        void set(int i, int j, int value) //设置矩阵第i行第j列元素值为value
        {
            p[i * cols + j] = value;
        }
        double& at(int i, int j)//返回矩阵第i行第j列元素的引用
        {
            return p[i * cols + j];
    }
        double at(int i, int j) const // 返回矩阵第i行第j列元素的值
        {
            return p[i * cols + j];
    }
    int get_lines() const //返回矩阵行数
    {
        return lines;
    }
    int get_cols() const //返回矩列数
    {
        return cols;
    }
    void print() const // 按行打印输出矩阵
    {
        for (int i = 0; i < lines; i++)
        {
            for (int j = 0; j < cols; j++)
                cout << at(i, j) << " ";
            cout << endl;
        }
    }
private:
    int lines; // 矩阵行数
    int cols; // 矩阵列数
    double* p; // 指向存放矩阵数据的内存块的首地址
};

task6.cpp

#include <iostream>
#include "matrix.hpp"
void test() {
using namespace std;
double x[] = {1, 2, 3, 4, 5, 6};
Matrix m1(3, 2); // 创建一个3×2的矩阵
m1.set(x); // 用一维数组x的值按行为矩阵m1赋值
m1.print(); // 打印矩阵m1的值
cout << "the first line is: " << endl;
cout << m1.at(0, 0) << " " << m1.at(0, 1) << endl; // 输出矩阵m1第1行两个元素的值
cout << endl;
Matrix m2(2, 3);
m2.set(x);
m2.print();
cout << "the first line is: " << endl;
cout << m2.at(0, 0) << " " << m2.at(0, 1) << " " << m2.at(0, 2) << endl;
cout << endl;
Matrix m3(m2); // 用矩阵m2构造新的矩阵m3
m3.set(0, 0, 999); // 将矩阵m3第0行第0列元素值设为999
m3.print();
}
int main() {
test();
}

结果

修改数值后结果