二分法求a^b(递归)
摘要:        
原理:b为偶数时,a^b = a^(b/2) * a^(b/2) = (a*a)^(b/2),如a^4 = a^2 * a^2 b为奇数时,a^b = a *a^(b/2) * a^(b/2) =a * (a*a)^(b/2),如a^5 = a *a^2 * a^2 LL A_b(LL a, LL b) { if (b == 0) { return 1; } LL temp = A_b(a*a, b >> 1); if(b & 1) { temp = t...    阅读全文
		
		posted @ 2012-03-21 11:05 [S*I]SImMon_WCG______* 阅读(218) 评论(0) 推荐(0)
 
                    
                     
                    
                 
                    
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