1 double Solution::findMedianSortedArrays(vector<int>& nums1, vector<int>& nums2)
2 {
3 if (nums1.size() > nums2.size())
4 {
5 return findMedianSortedArrays(nums2, nums1);
6 }
7
8 int m = nums1.size();
9 int n = nums2.size(); //m <= n
10
11 int left = 0, right = m, ansi=-1;
12 int midNum1 = 0, midNum2 = 0;
13 auto max = [](int a, int b)
14 {
15 return a >= b ? a : b;
16 };
17 auto min = [](int a, int b)
18 {
19 return a <= b ? a : b;
20 };
21 while (left <= right)
22 {
23 int i = (left + right) / 2;
24 int j = (m + n + 1) / 2 - i;
25
26 int i_1 = i == 0 ? INT_MIN : nums1[i - 1];
27 int i_0 = i == m ? INT_MAX : nums1[i];
28
29 int j_1 = j == 0 ? INT_MIN : nums2[j - 1];
30 int j_0 = j == n ? INT_MAX : nums2[j];
31 if (i_1 <= j_0)
32 {
33 ansi = i;
34 midNum1 = max(i_1, j_1);
35 midNum2 = min(i_0, j_0);
36 left = i + 1;
37 }
38 else
39 {
40 right = i - 1;
41 }
42 }
43 return (1 == (m + n) % 2) ? (double)midNum1 : (double)(midNum1 + midNum2) / 2;
44 }