php将图片以二进制保存到mysql数据库并显示

一.存储图片的数据表结构:

--
-- 表的结构 `image`
--

CREATE TABLE IF NOT EXISTS `image` (
  `id` int(3) NOT NULL AUTO_INCREMENT,
  `name` varchar(100) CHARACTER SET utf8 NOT NULL,
  `pic` blob NOT NULL,
  `type` varchar(50) CHARACTER SET utf8 NOT NULL,
  `date` datetime NOT NULL,
  PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ;

--
-- 转存表中的数据 `image`
--

  二.php将图片以二进制保存到mysql数据库中:

(1)连接数据库文件:conn.php:
<?php
$conn = mysql_connect('localhost', 'root', '');
mysql_select_db('study', $conn);
mysql_query("SET NAMES UTF-8");
?>

  (2)图片上传并以二进制保存到数据库文件:upload.php

<?php
include('./conn.php');
if ($_POST['submit']) {
    if ($_FILES['image']['size']) {
        $names = $_FILES['image']['name'];
        $arr   = explode('.', $names);
        $name  = $arr[0]; //图片名称
        $date  = date('Y-m-d H:i:s'); //上传日期
        $fp    = fopen($_FILES['image']['tmp_name'], 'rb');
        $type  = $_FILES['image']['type'];
        if (!$fp) {
            showInfo('读取图片失败!');
        } else {
            $image = addslashes(fread($fp, filesize($_FILES['image']['tmp_name'])));
            if ($image) {
                $q      = "insert into image (name, pic, type, date) values ('$name','$image','$type','$date')";
                $result = mysql_query($q);
                if ($result) {
                    showInfo('上传成功!');
                } else {
                    showInfo('上传失败!');
                }
                
            } else {
                showInfo('请选择要上传的文件!');
            }
        }
        
    } else {
        showInfo('请选择要上传的文件!');
    }
}


function showInfo($info)
{
    echo "<html><head><meta http-equiv=\"Content-Type\" content=\"text/html; charset=utf-8\" />";
    echo "<meta http-equiv='refresh' content='1;url=index.php'>";
    echo "</head>";
    echo "<body>" . $info . "……</body>";
    echo "</html>";
}
?>

  三.从数据库中读取以二进制保存的图片并显示:image.php

<?php
include('./conn.php');

$id     = $_GET['id'];
$sql    = "select * from image where id='$id'";
$result = mysql_query($sql, $conn);
if (!$result)
    die("读取图片失败!");
$num = mysql_num_rows($result);
if ($num < 1)
    die("暂无图片");
$data = mysql_result($result, 0, 'pic');
$type = mysql_result($result, 0, 'type');
mysql_close($id);
Header("Content-type: $type");
echo $data;
?>

  四.上传并显示图片的页面:index.php

<?php
include('./conn.php');
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
       "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

<html xmlns="http://www.w3.org/1999/xhtml" lang="en_US" xml:lang="en_US">
<!--
 * Created on 2012-10-20
 *
 * To change the template for this generated file go to
 * Window - Preferences - PHPeclipse - PHP - Code Templates
-->
 <head>
 <meta http-equive="Content-Type" content=text/html charset=utf-8>
  <title> </title>
 </head>
 <body>
 <form method='post' action='./upload.php' enctype="multipart/form-data">
<input type="file" name="image" />
<input type="submit" name="submit" value="上传" />
</form>
<!-----------显示图片--------------------->
<table>
<?php
$ret = mysql_query('select * from image order by id desc');
if ($ret) {
    while ($row = mysql_fetch_array($ret)) {
?>
<tr>
<td style='width:170px;'>
<img src="image.php?id=<?php
        echo $row[id];
?>"  width="170" height="150" border="0">
<div style='text-align:center;'><?php
        echo $row['name'];
?></div>
<?php
        echo $row['date'];
?>
</td>
</tr>
<?php
    }
}
?>
</table>
<!-----------/显示图片--------------------->
 </body>
</html>

  

posted @ 2015-10-26 00:17 热血夺刀,梦还长存 阅读(...) 评论(...) 编辑 收藏