摘要:        
Given a binary tree, find the lowest common ancestor (LCA) of two given nodes in the tree.According to thedefinition of LCA on Wikipedia: “The lowest ...    阅读全文
        
            posted @ 2015-08-08 19:41
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摘要:        
Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST.According to thedefinition of LCA on Wikipedia: ...    阅读全文
        
            posted @ 2015-08-08 18:34
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Given a singly linked list, determine if it is a palindrome.Follow up:Could you do it in O(n) time and O(1) space?/** * Definition for singly-linked l...    阅读全文
        
            posted @ 2015-08-08 18:04
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Given an integer n, count the total number of digit 1 appearing in all non-negative integers less than or equal to n.For example:Given n = 13,Return 6...    阅读全文
        
            posted @ 2015-08-08 17:32
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Implement the following operations of a queue using stacks.push(x) -- Push element x to the back of queue.pop() -- Removes the element from in front o...    阅读全文
        
            posted @ 2015-08-08 16:55
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Given an integer, write a function to determine if it is a power of two.public class Solution { //注意0和负数都返回false!!! /*public boolean isP...    阅读全文
        
            posted @ 2015-08-08 16:38
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Given a binary search tree, write a functionkthSmallestto find thekth smallest element in it.Note:You may assume k is always valid, 1 ≤ k ≤ BST's tota...    阅读全文
        
            posted @ 2015-08-08 16:15
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Given an integer array of sizen, find all elements that appear more than⌊ n/3 ⌋times. The algorithm should run in linear time and in O(1) space.public...    阅读全文
        
            posted @ 2015-08-08 15:54
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Given a sorted integer array without duplicates, return the summary of its ranges.For example, given[0,1,2,4,5,7], return["0->2","4->5","7"].public cl...    阅读全文
        
            posted @ 2015-08-08 15:16
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Implement a basic calculator to evaluate a simple expression string.The expression string contains onlynon-negativeintegers,+,-,*,/operators and empty...    阅读全文
        
            posted @ 2015-08-08 14:54
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