摘要: 交换类排序:冒泡 L = [1,3,2,4,1] n = len(L) for i in range(n-1, 0, -1): for j in range(1, i + 1): # 每趟比较的次数(第一趟比较n-1次) if L[j-1] > L[j]: temp = L[j] L[j] = L[ 阅读全文
posted @ 2020-08-22 00:11 绿茶编程 阅读(85) 评论(0) 推荐(0)