摘要: 二进制的基础 and & (按位取与) 1 & 1 = 1 1 & 0 = 0 0 & 0 = 0 0 & 1 = 0 or | (按位取或) 1 | 1 = 1 1 | 0 = 1 0 | 0 = 0 0 | 1 = 0 xor ⊕/^ (按位异或) 1⊕1 = 0 1⊕0 = 1 0 ⊕0 = 阅读全文
posted @ 2018-07-17 18:38 玥~endlessly~vast 阅读(242) 评论(0) 推荐(0)