摘要:
select * from bss_ppl t where exists (select 1 from bss_ppl where t.PROJECT_NO = PROJECT_NO group by PROJECT_NO having count(*) > 1) and rm in ('signe 阅读全文
posted @ 2017-04-01 16:01 _eve 阅读(164) 评论(0) 推荐(0)
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摘要:
select * from bss_ppl t where exists (select 1 from bss_ppl where t.PROJECT_NO = PROJECT_NO group by PROJECT_NO having count(*) > 1) and rm in ('signe 阅读全文
posted @ 2017-04-01 16:01 _eve 阅读(164) 评论(0) 推荐(0) |
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