摘要: 核心代码为 foldl (\x y -> x `xor` y) 0 $ filter (\x -> bits !! x /= 0) [0..length bits - 1] import Data.Bits solve bits = foldl (\x y -> x `xor` y) 0 $ fil 阅读全文
posted @ 2022-08-25 23:06 七つ一旋桜 阅读(36) 评论(0) 推荐(0)