摘要: function getUrlParameter(name){ name = name.replace(/[]/,"\[").replace(/[]/,"\[").replace(/[]/,"\\\]"); var regexS = "[\\?&]"+name+"=([^&#]*)"; var regex = new RegExp( regexS ); var results = regex.ex 阅读全文
posted @ 2019-09-07 18:47 小泉哥 阅读(6069) 评论(0) 推荐(0)