摘要:
function getUrlParameter(name){ name = name.replace(/[]/,"\[").replace(/[]/,"\[").replace(/[]/,"\\\]"); var regexS = "[\\?&]"+name+"=([^&#]*)"; var regex = new RegExp( regexS ); var results = regex.ex 阅读全文
posted @ 2019-09-07 18:47
小泉哥
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