ACM - 随笔分类(第5页) - pcoda

杭电acm2019数列有序!

摘要：数列有序! http://acm.hdu.edu.cn/showproblem.php?pid=2019 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission 阅读全文

posted @ 2011-05-13 17:01 pcoda 阅读(535) 评论(0) 推荐(0)

杭电acm2018母牛的故事

摘要：母牛的故事Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 15516 Accepted Submission(s): 7471 Problem 阅读全文

posted @ 2011-05-11 21:26 pcoda 阅读(654) 评论(0) 推荐(0)

杭电acm2015偶数求和

摘要：偶数求和 http://acm.hdu.edu.cn/showproblem.php?pid=2015 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission( 阅读全文

posted @ 2011-05-10 21:00 pcoda 阅读(452) 评论(0) 推荐(0)

杭电acm2012素数判定

摘要：素数判定 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 25001 Accepted Submission(s): 8429http://ac 阅读全文

posted @ 2011-05-04 19:57 pcoda 阅读(608) 评论(0) 推荐(0)

杭电acm2005第几天？

摘要：第几天？ http://acm.hdu.edu.cn/showproblem.php?pid=2006 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission( 阅读全文

posted @ 2011-05-03 21:56 pcoda 阅读(3465) 评论(0) 推荐(0)

杭电acm1012 u Calculate e

摘要：Problem Description A simple mathematical formula for e is where n is allowed to go to infinity. This can actually yield very accurate approximations 阅读全文

posted @ 2011-04-27 21:51 pcoda 阅读(300) 评论(0) 推荐(0)

杭电acm_1005Number Sequence

摘要：http://acm.hdu.edu.cn/showproblem.php?pid=1005 Number Sequence Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total 阅读全文

posted @ 2011-04-26 21:04 pcoda 阅读(859) 评论(1) 推荐(0)

杭电acm1003

摘要：http://acm.hdu.edu.cn/showproblem.php?pid=1003 Max Sum Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submissi 阅读全文

posted @ 2011-04-25 22:08 pcoda 阅读(917) 评论(0) 推荐(0)

大数相乘

摘要：输入两个大数，输出两个数的乘积，位数可能很大，少于1000位一个数的第i位和另一个数的第j位相乘所得的数，一定是要累加到结果的第i+j位上，这里i，j都是自由往左从0开始数。 #include<stdio.h> #include<string.h> #define MAX_LEN 1000 uns 阅读全文

posted @ 2011-04-24 18:06 pcoda 阅读(222) 评论(0) 推荐(0)

大数相加

摘要：输入两个大数，输出两数之和 #include<stdio.h> #include<string.h> #define MAX_LEN 10001 int an1[MAX_LEN+10]; int an2[MAX_LEN+10]; char szLine1[MAX_LEN+10]; char szLi 阅读全文

posted @ 2011-04-24 18:05 pcoda 阅读(169) 评论(0) 推荐(0)

杭电acm2031 进制转换

摘要：http://acm.hdu.edu.cn/showproblem.php?pid=2031 进制转换 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s 阅读全文

posted @ 2011-04-24 17:57 pcoda 阅读(479) 评论(2) 推荐(0)

杭电acm1008 Elevator

摘要：http://acm.hdu.edu.cn/showproblem.php?pid=1008 Elevator Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submiss 阅读全文

posted @ 2011-04-24 17:54 pcoda 阅读(235) 评论(0) 推荐(0)

杭电acm1002 Sum Problem

摘要：http://acm.hdu.edu.cn/showproblem.php?pid=1001 Sum Problem Time Limit: 1000/500 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submi 阅读全文

posted @ 2011-04-24 17:46 pcoda 阅读(901) 评论(0) 推荐(0)

随笔分类 - ACM