C(C++)运算符

一下摘自:http://www.cppreference.com/operator_precedence.html

The operators at the top of this list are evaluated first. Operators within a group have the same precedence. All operators have left-to-right associativity unless otherwise noted.

Operator Description Example Overloadable
Group 1 (no associativity)
:: Scope resolution operator Class::age = 2; NO
Group 2
() Function call isdigit('1') YES
() Member initalization c_tor(int x, int y) : _x(x), _y(y*10){}; YES
[] Array access array[4] = 2; YES
-> Member access from a pointer ptr->age = 34; YES
. Member access from an object obj.age = 34; NO
++ Post-increment for( int i = 0; i < 10; i++ ) cout << i; YES
-- Post-decrement for( int i = 10; i > 0; i-- ) cout << i; YES
const_cast Special cast const_cast<type_to>(type_from); NO
dynamic_cast Special cast dynamic_cast<type_to>(type_from); NO
static_cast Special cast static_cast<type_to>(type_from); NO
reinterpret_cast Special cast reinterpret_cast<type_to><type_from>; NO
typeid Runtime type information cout « typeid(var).name(); NO
Group 3 (right-to-left associativity)
! Logical negation if( !done ) … YES
not Alternate spelling for !
~ Bitwise complement flags = ~flags; YES
compl Alternate spelling for ~
++ Pre-increment for( i = 0; i < 10; ++i ) cout << i; YES
-- Pre-decrement for( i = 10; i > 0; --i ) cout << i; YES
- Unary minus int i = -1; YES
+ Unary plus int i = +1; YES
* Dereference int data = *intPtr; YES
& Address of int *intPtr = &data; YES
new Dynamic memory allocation long *pVar = new long; YES
delete Deallocating the memory delete pVar; YES
(type) Cast to a given type int i = (int) floatNum; YES
sizeof Return size of an object int size = sizeof(floatNum); NO
Group 4
->* Member pointer selector ptr->*var = 24; YES
.* Member object selector obj.*var = 24; NO
Group 5
* Multiplication int i = 2 * 4; YES
/ Division float f = 10.0 / 3.0; YES
% Modulus int rem = 4 % 3; YES
Group 6
+ Addition int i = 2 + 3; YES
- Subtraction int i = 5 - 1; YES
Group 7
<< Bitwise shift left int flags = 33 << 1; YES
>> Bitwise shift right int flags = 33 >> 1; YES
Group 8
< Comparison less-than if( i < 42 ) … YES
<= Comparison less-than-or-equal-to if( i <= 42 ) ... YES
> Comparison greater-than if( i > 42 ) … YES
>= Comparison greater-than-or-equal-to if( i >= 42 ) ... YES
Group 9
== Comparison equal-to if( i == 42 ) ... YES
eq Alternate spelling for ==
!= Comparison not-equal-to if( i != 42 ) … YES
not_eq Alternate spelling for !=
Group 10
& Bitwise AND flags = flags & 42; YES
bitand Alternate spelling for &
Group 11
^ Bitwise exclusive OR (XOR) flags = flags ^ 42; YES
xor Alternate spelling for ^
Group 12
| Bitwise inclusive (normal) OR flags = flags | 42; YES
bitor Alternate spelling for |
Group 13
&& Logical AND if( conditionA && conditionB ) … YES
and Alternate spelling for &&
Group 14
|| Logical OR if( conditionA || conditionB ) ... YES
or Alternate spelling for ||
Group 15 (right-to-left associativity)
? : Ternary conditional (if-then-else) int i = (a > b) ? a : b; NO
Group 16 (right-to-left associativity)
= Assignment operator int a = b; YES
+= Increment and assign a += 3; YES
-= Decrement and assign b -= 4; YES
*= Multiply and assign a *= 5; YES
/= Divide and assign a /= 2; YES
%= Modulo and assign a %= 3; YES
&= Bitwise AND and assign flags &= new_flags;
and_eq Alternate spelling for &=
^= Bitwise exclusive or (XOR) and assign flags ^= new_flags; YES
xor_eq Alternate spelling for ^=
|= Bitwise normal OR and assign flags |= new_flags; YES
or_eq Alternate spelling for |=
<<= Bitwise shift left and assign flags <<= 2; YES
>>= Bitwise shift right and assign flags >>= 2; YES
Group 17
throw throw exception throw EClass(“Message”); NO
Group 18
, Sequential evaluation operator for( i = 0, j = 0; i < 10; i++, j++ ) … YES

Order of Evaluation and of Side Effects

One important aspect of C++ that is related to operator precedence is the order of evaluation and the order of side effects in expressions. In some circumstances, the order in which things happen is not defined. For example, consider the following code:

    float x = 1;
x = x / ++x;

The value of x is not guaranteed to be consistent across different compilers, because it is not clear whether the computer should evaluate the left or the right side of the division first. Depending on which side is evaluated first, x could take a different value.

Furthermore, while ++x evaluates to x+1, the side effect of actually storing that new value in x could happen at different times, resulting in different values for x.

The bottom line is that expressions like the one above are horribly ambiguous and should be avoided at all costs. When in doubt, break a single ambiguous expression into multiple expressions to ensure that the order of evaluation is correct.

posted @ 2009-03-09 16:45  红袖添香  阅读(1264)  评论(0编辑  收藏  举报