摘要: SELECT * FROM your_table WHERE date_column >= CURDATE() - INTERVAL 30 DAY 阅读全文
posted @ 2025-04-08 23:59 程序员の奇妙冒险 阅读(13) 评论(0) 推荐(0)
摘要: SELECT object_id, SUM(CASE WHEN date_column >= CURDATE() - INTERVAL 30 DAY AND date_column < CURDATE() THEN amount ELSE 0 END) AS amount_30_days, SUM( 阅读全文
posted @ 2025-04-08 23:59 程序员の奇妙冒险 阅读(26) 评论(0) 推荐(0)
摘要: /*获取指定id的上一条记录,我这里是以id=5为例的*/ select cid,cname from company order by cid>=5,cid desc limit 1 /*获取指定id的下一条记录,我这里是以id=5为例的*/ SELECT cid,cname from compa 阅读全文
posted @ 2025-04-08 23:58 程序员の奇妙冒险 阅读(82) 评论(0) 推荐(0)
摘要: SELECT * FROM tb_product WHERE create_date BETWEEN STR_TO_DATE( date_format( CURRENT_DATE (), '%Y-%m-01 00:00:00' ), '%Y-%m-%d %H:%i:%s' ) AND STR_TO_ 阅读全文
posted @ 2025-04-08 23:58 程序员の奇妙冒险 阅读(17) 评论(0) 推荐(0)
摘要: 创建表 Create table If Not Exists Scores (Id int, Score DECIMAL(3,2)); insert into Scores (Id, Score) values ('1', '3.5'); insert into Scores (Id, Score) 阅读全文
posted @ 2025-04-08 23:57 程序员の奇妙冒险 阅读(43) 评论(0) 推荐(0)
摘要: SELECT * FROM sys_menu WHERE id in ( select id from ( select t1.id, if(find_in_set(parent_id, @pids) > 0, @pids := concat(@pids, ',', id), 0) as ischi 阅读全文
posted @ 2025-04-08 23:56 程序员の奇妙冒险 阅读(53) 评论(0) 推荐(0)
摘要: 分类递归查询子节点 delimiter $$ drop function if exists get_child_categoryt$$ create function get_child_categoryt(in_id varchar(10)) returns varchar(1000) begi 阅读全文
posted @ 2025-04-08 23:55 程序员の奇妙冒险 阅读(32) 评论(0) 推荐(0)
摘要: //status = 0 为未支付状态 select * FROM order WHERE TIMESTAMPDIFF(MINUTE,create_date,now()) > 20 AND status = 0; 阅读全文
posted @ 2025-04-08 23:52 程序员の奇妙冒险 阅读(18) 评论(0) 推荐(0)
摘要: -- 返回的是某月某日的数量 SELECT monthDay, count( 0 ) AS numb FROM ( SELECT -- 返回的是月日 date_format( create_date, '%m-%d' ) monthDay FROM tb_product WHERE create_d 阅读全文
posted @ 2025-04-08 23:52 程序员の奇妙冒险 阅读(27) 评论(0) 推荐(0)
摘要: Logins table: + + + | user_id | login_date | + + + | 1 | 2019-07-20 | | 1 | 2019-07-20 | | 1 | 2019-07-20 | | 2 | 2019-07-20 | | 2 | 2019-07-21 | | 2 阅读全文
posted @ 2025-04-08 23:51 程序员の奇妙冒险 阅读(12) 评论(0) 推荐(0)
摘要: 近 30天的每日活跃用户数(当天只要有一条活动记录,即为活跃用户)。 Activity table: + + + + + | user_id | session_id | activity_date | activity_type | + + + + + | 1 | 1 | 2019-07-20 | 阅读全文
posted @ 2025-04-08 23:50 程序员の奇妙冒险 阅读(41) 评论(0) 推荐(0)
摘要: 这种查询会导致全表扫描 select id,name,create_date from sys_user a where not exists (select * from sys_user b where a.name = b.name and a.create_date < create_dat 阅读全文
posted @ 2025-04-08 23:49 程序员の奇妙冒险 阅读(16) 评论(0) 推荐(0)
摘要: drop procedure if exists init_group_val; delimiter $ create PROCEDURE init_group_val() BEGIN DECLARE group_id VARCHAR(64); -- 遍历数据结束标志 DECLARE done IN 阅读全文
posted @ 2025-04-08 23:46 程序员の奇妙冒险 阅读(24) 评论(0) 推荐(0)
摘要: select a.id,substring_index(substring_index(a.val,',',b.help_topic_id+1),',',-1) from tbl_brand_attr_group a join mysql.help_topic b on b.help_topic_i 阅读全文
posted @ 2025-04-08 23:43 程序员の奇妙冒险 阅读(27) 评论(0) 推荐(0)
摘要: delimiter $ create PROCEDURE phoneDeal() BEGIN DECLARE ids varchar(64); -- 遍历数据结束标志 DECLARE done INT DEFAULT FALSE; -- 游标 DECLARE cur_account CURSOR F 阅读全文
posted @ 2025-04-08 23:42 程序员の奇妙冒险 阅读(9) 评论(0) 推荐(0)
摘要: DELIMITER $$ drop procedure if exists getCategoryAndBrandRankByOrderId $$ CREATE PROCEDURE getCategoryAndBrandRankByOrderId ( _index int, size int ) B 阅读全文
posted @ 2025-04-08 23:41 程序员の奇妙冒险 阅读(19) 评论(0) 推荐(0)
摘要: 解决MySQL sql_mode=only_full_group_by问题,this is incompatible with sql_mode=only_full_group_by错误 原因: 看一下group by的语法: select 选取分组中的列 + 聚合函数 from 表名称 group 阅读全文
posted @ 2025-04-08 23:38 程序员の奇妙冒险 阅读(220) 评论(0) 推荐(0)
摘要: create_time 时间不超过当前系统时间 7 天的数据 select create_time from incentive_activity_pub where DATEDIFF(CURDATE(), create_time)<=7 阅读全文
posted @ 2025-04-08 23:35 程序员の奇妙冒险 阅读(33) 评论(0) 推荐(0)
摘要: DELIMITER // drop procedure if exists sys_columns_nodes// create procedure sys_columns_nodes(in rootid int) begin declare stemp varchar(1000);/*定义一个临时 阅读全文
posted @ 2025-04-08 23:34 程序员の奇妙冒险 阅读(11) 评论(0) 推荐(0)
摘要: select FROM_UNIXTIME(1678723200000/1000,'%Y-%m-%d %H:%i:%S') as date 输出 2023-03-14 00:00:00 阅读全文
posted @ 2025-04-08 23:31 程序员の奇妙冒险 阅读(29) 评论(0) 推荐(0)