约瑟夫问题

/*
 * 功能:约瑟夫问题(丢手帕)
 */
package com.jitao;
 
public class demo3 {
 
    public static void main(String[] args) {
        // TODO Auto-generated method stub
        CycLink cyclink=new CycLink();
        cyclink.setLen(5);
        cyclink.createLink();
        cyclink.setK(1);
        cyclink.setM(2);
        cyclink.show();
        cyclink.play();
    }
 
}
 
class Child
{
    int no;
    Child nextChild=null;
    public Child(int no)
    {
        //给一个编号
        this.no=no;
    }
}
 
//环形链表
class CycLink
{
    //先定义一个指向链表第一个小孩的引用
    //指向第一个小孩的引用,不能动
    Child firstChild=null;
    Child temp=null;
    int len=0;//表示共有几个小孩
    int k=0;
    int m=0;
     
    //设置链表的大小
    public void setLen(int len)
    {
        this.len=len;
    }
     
    //设置从第几个人开始数数
    public void setK(int k)
    {
        this.k=k;
    }
     
    //设置m
    public void setM(int m)
    {
        this.m=m;
    }
     
    //开始Play
    public void play()
    {
        Child temp=this.firstChild;
         
        //1.先找到开始数数的人
        for(int i=0;i<k;i++)
        {
            temp=temp.nextChild;
        }
         
        while(this.len!=1){
        //2.数m下
        for(int j=1;j<m;j++)
        {
            temp=temp.nextChild;
        }
        //找到要出圈的前一个小孩
        Child temp2=temp;
        while(temp2.nextChild!=temp)
        {
            temp2=temp2.nextChild;
        }
         
        //3.将数到m的小孩,退出圈
        temp2.nextChild=temp.nextChild;
        //让temp指向下一个数数的小孩
        temp=temp.nextChild;
        this.len--;
        }
        //最后一个小孩
        System.out.println("最后出圈"+temp.no);
    }
     
    //
     
     
    //初始化环形链表
    public void createLink()
    {
        for(int i=1;i<=len;i++)
        {
            if(i==1){
            //创建第一个小孩
            Child ch=new Child(i);
            this.firstChild=ch;
            this.temp=ch;
            }else
            {
                //创建最后一个小孩
                if(i==len)
                {
                    //继续创建小孩
                    Child ch=new Child(i);
                    temp.nextChild=ch;
                    temp=ch;
                    temp.nextChild=this.firstChild;
                }
                else
                {
                    //继续创建小孩
                    Child ch=new Child(i);
                    temp.nextChild=ch;
                    temp=ch;
                }
            }
        }
    }
    //打印该环形链表
    public void show()
    {
        //定义一个跑龙套
        Child temp=this.firstChild;
        do{
            System.out.println(temp.no+" ");
            temp=temp.nextChild;
        }while(temp!=this.firstChild);
    }
}

posted on 2016-04-24 22:29  难知如阴凌沧海  阅读(179)  评论(0)    收藏  举报

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