Java|PTA乙级|1008 数组元素循环右移问题 (20分)|解析
解析答案如下:
import java.util.Scanner;
//思路:想的简单点,把数组循环改成数组输出数字的先后顺序,先输出后几位,再输出前几位!
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
int cishu = sc.nextInt();
int[] arr = new int[n];
for (int i = 0; i < n; i++) {
arr[i] = sc.nextInt();
}
reverse(arr, cishu);
}
public static void reverse(int[] arr, int cishu) {
int a = 0, b = 0;
a=arr.length;
//这是一个坑,测试点2和测试点3会输入循环次数大于数组长度的数
a %=cishu;
for (int i = 0; i < cishu; i++) {
System.out.print(arr[arr.length - cishu + i] + " ");
}
for (int i = 0; i < arr.length - cishu; i++) {
if (i != arr.length - cishu - 1) {
System.out.print(arr[i]+" ");
} else {
System.out.print(arr[arr.length - cishu - 1]);
}
}
}
}