BZOJ4003 JLOI2015城池攻占

用左偏树模拟攻占的过程，维护最小值，最多入和出m次，每次log复杂度。

 1 #include<bits/stdc++.h>
 2 using namespace std;
 3 const int N=3e5+10;
 4 typedef long long ll;
 5 ll w[N],v[N],mul[N],add[N],h[N];
 6 int l[N],r[N],dis[N],flag[N],c[N],rt[N],head[N],f[N],d[N],die[N],a[N],n,m,cnt;
 7 struct edge
 8 {
 9     int to,nex;
10 }e[N<<1];
11 void adde(int x,int y)
12 {
13     e[++cnt].to=y;e[cnt].nex=head[x];head[x]=cnt;
14 }
15 void pushdown(int x)
16 {
17     if(mul[x]>1)
18     {
19         mul[l[x]]*=mul[x];mul[r[x]]*=mul[x];
20         add[l[x]]*=mul[x];add[r[x]]*=mul[x];
21     }
22     if(add[x])
23     {
24         add[l[x]]+=add[x];add[r[x]]+=add[x];
25     }
26     w[l[x]]*=mul[x];w[l[x]]+=add[x];
27     w[r[x]]*=mul[x];w[r[x]]+=add[x];
28     mul[x]=1;add[x]=0;
29 }
30 int merge(int x,int y)
31 {
32     if(!x||!y)return x+y;
33     pushdown(x);pushdown(y);
34     if(w[x]>w[y])swap(x,y);
35     r[x]=merge(r[x],y);
36     if(dis[r[x]]>dis[l[x]])swap(l[x],r[x]);
37     dis[x]=dis[r[x]]+1;
38     return x;
39 }
40 void dfs(int x,int fa)
41 {
42     for(int i=head[x];i;i=e[i].nex)
43     {
44         int y=e[i].to;
45         if(y==fa)continue;
46         d[y]=d[x]+1;dfs(y,x);rt[x]=merge(rt[x],rt[y]);
47     }
48     while(rt[x]&&w[rt[x]]<h[x])
49     {
50         pushdown(rt[x]);
51         die[rt[x]]=d[c[rt[x]]]-d[x];
52         flag[x]++;rt[x]=merge(l[rt[x]],r[rt[x]]);
53     }
54     if(a[x])mul[rt[x]]*=v[x],add[rt[x]]*=v[x],w[rt[x]]*=v[x],pushdown(rt[x]);
55     else add[rt[x]]+=v[x],w[rt[x]]+=v[x],pushdown(rt[x]);
56     return;
57 }
58 int main()
59 {
60     scanf("%d%d",&n,&m);
61     for(int i=1;i<=n;++i)scanf("%lld",&h[i]);
62     for(int i=2;i<=n;++i)
63     {
64         scanf("%d%d%lld",&f[i],&a[i],&v[i]);
65         adde(i,f[i]);adde(f[i],i);
66     }
67     for(int i=1;i<=m;++i)
68     {
69         scanf("%lld%d",&w[i],&c[i]);
70         rt[c[i]]=merge(rt[c[i]],i);
71         mul[i]=1;
72     }
73     d[1]=1;dfs(1,0);
74     while(rt[1])pushdown(rt[1]),die[rt[1]]=d[c[rt[1]]],rt[1]=merge(l[rt[1]],r[rt[1]]);
75     for(int i=1;i<=n;++i)printf("%d\n",flag[i]);
76     for(int i=1;i<=m;++i)printf("%d\n",die[i]);
77     return 0;
78 }

 

posted @ 2018-03-02 11:53  大奕哥&VANE  阅读(150)  评论(0)  编辑  收藏  举报