摘要: 1.lowbite :i&-i; 2.c[i]=x[i-lowbite(i)+1]+x[i-lowbite(i)+2]+x[i-lowbite(i)+3]+.....+x[i]; 3.for(int i=k;i>=0;i-=lowbite(i)) sum[k]+=c[i]; 4.点修改:for(in 阅读全文
posted @ 2017-12-24 08:19 马子涵 阅读(134) 评论(0) 推荐(0)