摘要:
October 25,2025 Today is Saturday,and it's windy.I went to the company to work as usual,but this is considered overtime.Because there are two days to 阅读全文
posted @ 2025-10-25 11:02
万能包哥
阅读(6)
评论(0)
推荐(0)
|
摘要:
October 25,2025 Today is Saturday,and it's windy.I went to the company to work as usual,but this is considered overtime.Because there are two days to 阅读全文
posted @ 2025-10-25 11:02
万能包哥
阅读(6)
评论(0)
推荐(0)
摘要:
Welcome to my channel Bookish English 2! Have you ever dreamed of speaking English… but felt too shy, too slow, or just not good enough? Well, I have 阅读全文
posted @ 2025-10-20 22:32
万能包哥
阅读(17)
评论(0)
推荐(0)
摘要:
Welcome to my channel, Bookish English 2. Do you study English, learn grammar, memorize words, but when it's time to speak, nothing comes out? Your mi 阅读全文
posted @ 2025-10-19 20:18
万能包哥
阅读(19)
评论(0)
推荐(0)
摘要:
At my level, an influencer with this many followers, if I do a live stream PK battle, the money I'd make would be easy. Rain or shine, I'll be waiting 阅读全文
posted @ 2025-10-18 20:23
万能包哥
阅读(10)
评论(0)
推荐(0)
摘要:
when I was in gomi particularly I felt very very close to a great spiritual [Music] power if we think of the Bible it would be in which we live and mo 阅读全文
posted @ 2025-10-18 19:20
万能包哥
阅读(7)
评论(0)
推荐(0)
摘要:
Welcome to Bookish English 2. Tell me honestly, how many times have you said, "I'll start learning English tomorrow." But tomorrow never comes, right? 阅读全文
posted @ 2025-10-18 18:21
万能包哥
阅读(10)
评论(0)
推荐(0)
摘要:
Welcome to my channel, Bookish English 2. Today I will show you something real. Last week I met a student who spoke English with only 50 sentences. Sh 阅读全文
posted @ 2025-10-14 22:35
万能包哥
阅读(23)
评论(0)
推荐(0)
摘要:
Welcome back to my channel, Bookish English. Today's video is all about the most powerful English books that every beginner must read before 2026. The 阅读全文
posted @ 2025-10-13 22:32
万能包哥
阅读(13)
评论(0)
推荐(0)
摘要:
Hello my friends and welcome back to Bookish English 2, the place where you live English, not just study it. Today's lesson is special. You will not r 阅读全文
posted @ 2025-10-12 14:20
万能包哥
阅读(8)
评论(0)
推荐(0)
摘要:
给你一个非负整数数组 nums ,你最初位于数组的 第一个下标 。数组中的每个元素代表你在该位置可以跳跃的最大长度。 判断你是否能够到达最后一个下标,如果可以,返回 true ;否则,返回 false 。 class Solution { public boolean canJump(int[] n 阅读全文
posted @ 2025-10-10 16:15
万能包哥
阅读(7)
评论(0)
推荐(0)
|