lambda; sort the dict; save the dict

$ cat label_cal.py
# count function; lambda;  sort the dict;  save the dict
#https://www.cnblogs.com/wind-wang/p/6090708.html
#https://www.cnblogs.com/wind-wang/p/6090708.html
category = []
test = []
file_name = "./label_0417.txt"
result = {}
result_1 = {}

with open(file_name,'r') as f:
     for line in f.readlines():
         line = line.strip('\n')
         cat = line.split('"')[-2]
         test.append(cat)         # the test is to save all the category
         if cat not in category:
            category.append(cat)  # teh category is to reduce the repeated category
     #print(test.count('pne'))    # use count funtion to calculate the total number in the list
     for i in category:
         #print("{}: {}".format(i,test.count(i)))
         result[i] = test.count(i)   # result is a dict, it saves the pairs of categories and counts.

     for k,v in result.items():
         if v > 200:              # if value is lower than 200, bypass
            result_1[k] = v       # save the k and v to a new dict

     for k,v in result_1.items():   #print the result_1 via specific format
         print('"{}": {}'.format(k,v))

     print("\nThere are {} classes which have more than 200 images".format(len(result_1)))
     print("Below are sorted dict from high to low\n")
     #result_1 = sorted(result.items(),key=lambda d:d[1],reverse=True)     #method 1, to sort the value
     result_1 = sorted(result_1.items(), lambda x, y: cmp(x[1], y[1]), reverse=True)   # method 2, to sort the value
     for k,v in result_1:       #print the result_1 via specific format. Note: result_1 type has been "list"
         print('"{}": {}'.format(k,v))

     print(type(result_1))


'''
result = {}
result = result.fromkeys(test)   # fromkeys can remove the repeated category
print(result)
category = list(result.keys())
print(category)

for i in category:
    result[i] = test.count(i)
print(result)
'''