WooKinson

摘要： 示例代码: #include <stdio.h>#define N 16 void dg(int a){ int y = a%N; int next = (a-y)/N; if (next) { dg(next); } if (y>9) { printf("%c",65+y%10); } else 阅读全文

摘要： 示例代码: #include <stdio.h> int main(void){ int n = 0 ; scanf("%d",&n); int i = 0 ; int a = 0 , b = 0 , c = 0 , d = 0 , e = 0 , f = 0; for (i = 10000 ; i 阅读全文

摘要： 示例代码: #include <stdio.h> int main(void){ int i = 0 ; int a = 0 , b = 0 , c = 0 , d = 0 ; for (i = 1000 ; i < 10000 ; i ++) { a = i/1000; b = i/100%10; 阅读全文