CF 586A 找1的个数和101的个数

Sample test(s)
input
5
0 1 0 1 1
output
4
input
7
1 0 1 0 0 1 0
output
4
input
1
0
output
0

 1 # include <iostream>
 2 # include <cstdio>
 3 # include <cstring>
 4 # include <algorithm>
 5 # include <string>
 6 # include <cmath>
 7 # include <queue>
 8 # define LL long long
 9 using namespace std ;
10 
11 int a[200] ;
12 
13 int main()
14 {
15     int n;
16     while(scanf("%d",&n) != EOF)
17     {
18        int i ;
19        int sum = 0 ;
20        int x ;
21        for (i = 0 ; i < n  ; i++)
22        {
23            scanf("%d" , &x) ;
24            if (x == 1)
25              sum++ ;
26            a[i] = x ;
27        }
28        for (i = 0 ; i < n  ; i++)
29        {
30            if (a[i] == 0)
31              continue ;
32            if (a[i] == 1 && a[i+1] == 0 && a[i+2] ==1)
33              sum++ ;
34        }
35        printf("%d\n" , sum) ;
36 
37     }
38     return 0;
39 }
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posted @ 2015-10-13 23:01  __Meng  阅读(181)  评论(0)  编辑  收藏  举报