摘要:
1 class Solution { 2 public: 3 int lastRemaining(int n, int m) { 4 if(n==1)return 0; 5 return (m%n+lastRemaining(n-1,m))%n;//以m%n为参考系,当成0,求得n-1的解再换系;也 阅读全文
posted @ 2021-12-31 19:40
matt-11
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摘要:
1 const int N=1e5+5; 2 class Solution { 3 public: 4 int ch[N][26]; 5 vector<string> findAllConcatenatedWordsInADict(vector<string>& words) { 6 unorder 阅读全文
posted @ 2021-12-31 17:45
matt-11
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