task4

#pragma once
#include<iostream>
using namespace std;

class vectorInt
{
public:
     vectorInt(int n);
     vectorInt(int n, int value);
     vectorInt(const vectorInt& v);
     ~vectorInt();
     int& at(int i);
     int get_size();
     friend void output(vectorInt& v);
 private:
     int size;
     int * p;
};
vectorInt::vectorInt(int n) : size(n) {
    cout << "constructor 1 called" << endl;
    p = new int[n];
}
vectorInt::vectorInt(int n, int value) : size(n)
{
    cout << "constructor 2 called" << endl;
    p = new int[n];
    for (int i = 0; i < n; i++)
        p[i] = value;
}
vectorInt::vectorInt(const vectorInt& v):size(v.size)
{
    cout << "copy constructor called" << endl;
    p = new int[size];
    for (int i = 0; i < size; i++)
        p[i] = v.p[i];
}
vectorInt::~vectorInt()
{
    cout << "destructor called" << endl;
    delete[]p;
}
int& vectorInt::at(int i)
{
    return p[i];
}
int vectorInt::get_size()
{
    return size;
}
void output(vectorInt& v)
{
    for (int i = 0; i < v.size; i++)
        cout << v.p[i]<<",";
    cout << endl;
}

 

 

#pragma once

#include <iostream>


using std::cout;
using std::endl;

class Matrix {
public:
    Matrix(int n);                     // 构造函数,构造一个n*n的矩阵
    Matrix(int n, int m);              // 构造函数,构造一个n*m的矩阵
    Matrix(const Matrix& X);           // 复制构造函数,使用已有的矩阵X构造
    ~Matrix();                         //析构函数

    void set(const double* pvalue);     // 用pvalue指向的连续内存块数据按行为矩阵赋值
    void set(int i, int j, int value); //设置矩阵第i行第j列元素值为value
    double& at(int i, int j);          //返回矩阵第i行第j列元素的引用
    double at(int i, int j) const;     // 返回矩阵第i行第j列元素的值
    int get_lines() const;             //返回矩阵行数
    int get_cols() const;              //返回矩列数
    void print() const;                // 按行打印输出矩阵

private:
    int lines; // 矩阵行数
    int cols;  // 矩阵列数
    double* p; // 指向存放矩阵数据的内存块的首地址
};
Matrix::Matrix(int n) :lines(n), cols(n)
{
    p = new double[n*n];
}
Matrix::Matrix(int n, int m) :lines(n), cols(m)
{
    p = new double[n * m];
}
Matrix::Matrix(const Matrix& X): lines(X.lines),cols(X.cols)
{
    p = new double[lines * cols];
    for (int i = 0; i < lines * cols; i++)
        p[i] = X.p[i];
}
Matrix::  ~Matrix() {};

void Matrix::set(const double* pvalue)
{
    for (int i = 0; i < lines * cols; i++)
        p[i] = pvalue[i];
}
void Matrix::set(int i, int j, int value)
{
    p[(i + 1) * (j + 1) - 1] = value;
}
double& Matrix:: at(int i, int j)
{
    return p[(i + 1) * (j + 1) - 1];
}
double Matrix::at(int i, int j)const
{
    return p[(i + 1) * (j + 1) - 1];
}
int Matrix::get_lines() const
{
    return lines;
}
int Matrix::get_cols() const
{
    return cols;
}
void Matrix::print() const
{
    for (int i = 0; i < lines * cols; i++)
    {
        if ((i + 1) % cols == 0)
        {
         cout << p[i] << " ";
         cout << endl;
        }
        else
            cout << p[i] << " ";
    }
}
#include <iostream>
#include "matrix.hpp"

void test() {
    using namespace std;

    double x[] = { 1, 2, 3, 4, 5, 6};

    Matrix m1(3, 2);    // 创建一个3×2的矩阵
    m1.set(x);          // 用一维数组x的值按行为矩阵m1赋值
    m1.print();         // 打印矩阵m1的值
    cout << "the first line is: " << endl;
    cout << m1.at(0, 0) << " " << m1.at(0, 1) << endl;  // 输出矩阵m1第1行两个元素的值
    cout << endl;

    Matrix m2(2, 3);
    m2.set(x);
    m2.print();
    cout << "the first line is: " << endl;
    cout << m2.at(0, 0) << " " << m2.at(0, 1) << " " << m2.at(0, 2) << endl;
    cout << endl;

    Matrix m3(m2);      // 用矩阵m2构造新的矩阵m3
    m3.set(0, 0, 999);  // 将矩阵m3第0行第0列元素值设为999
    m3.print();
}

int main() {
    test();
}

 

posted @ 2022-11-03 15:36  lzy1  阅读(20)  评论(0编辑  收藏  举报