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摘要: Given a string S, count the number of distinct, non-empty subsequences of S . Since the result may be large, return the answer modulo 10^9 + 7. Exampl 阅读全文
posted @ 2020-03-18 03:09 Review->Improve 阅读(191) 评论(0) 推荐(0)
摘要: Given 2 integers u and v, find the shortest array such that bitwise-xor of its elements is u, and the sum of its elements is v. Input The only line co 阅读全文
posted @ 2020-03-17 07:11 Review->Improve 阅读(296) 评论(0) 推荐(0)
摘要: Given the string s, return the size of the longest substring containing each vowel an even number of times. That is, 'a', 'e', 'i', 'o', and 'u' must 阅读全文
posted @ 2020-03-08 05:19 Review->Improve 阅读(758) 评论(0) 推荐(0)
摘要: Primitive Primes : two integers are coprime if their GCD is 1. If a number A is not divisible by another prime number P, then A and P are guranteed to 阅读全文
posted @ 2020-03-05 23:19 Review->Improve 阅读(148) 评论(0) 推荐(0)
摘要: Given a m x n grid. Each cell of the grid has a sign pointing to the next cell you should visit if you are currently in this cell. The sign of grid[i] 阅读全文
posted @ 2020-03-02 08:23 Review->Improve 阅读(1029) 评论(0) 推荐(0)
摘要: An interesting problem using suffix sum. For each wrong tries that is correct until after index p[i], we add 1 to cnt[p[i]]. This represents that all 阅读全文
posted @ 2020-03-01 06:31 Review->Improve 阅读(129) 评论(0) 推荐(0)
摘要: Problem Statement Link Clarification: The problem states that for each pair of points, we consider the minimum possible distance over any possible mom 阅读全文
posted @ 2020-02-28 23:07 Review->Improve 阅读(362) 评论(0) 推荐(0)
摘要: Given an array A of positive integers, call a (contiguous, not necessarily distinct) subarray of A good if the number of different integers in that su 阅读全文
posted @ 2020-02-04 11:41 Review->Improve 阅读(309) 评论(0) 推荐(0)
摘要: We are given an array A of N lowercase letter strings, all of the same length. Now, we may choose any set of deletion indices, and for each string, we 阅读全文
posted @ 2020-02-04 06:23 Review->Improve 阅读(334) 评论(0) 推荐(0)
摘要: You have some sticks with positive integer lengths. You can connect any two sticks of lengths X and Y into one stick by paying a cost of X + Y. You pe 阅读全文
posted @ 2020-01-24 05:55 Review->Improve 阅读(440) 评论(0) 推荐(0)
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