01 2022 档案
摘要:A. Counting Kangaroos is Fun There can be only at most N / 2 hold and held pairs based the problem's statment. So a greedy approach is just to divide
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摘要:Problem First I thought about modelling this problem as a directed graph, where between each pair of nodes, an edge represents a valid < > or > < tran
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摘要:Problem S: the set of numbers said by player 1; P: the set of numbers said by player 2; S^2 * P = a; S * P^2 = b; a * b = (S * P)^3, so a * b must be
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摘要:Problem Each fence is increased at most 2 times, so dp[i][j] is the min cost to make A[0, i] great with the last fence A[i] increased j times. The ans
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摘要:Problem Key idea: 1. for any substring s, if we can do not consider padding prefix 0s, its decimal value is always >= its length. 2. Appending a binar
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