js解析url参数返回json格式
urlQueryString:function(url){//scoreRecode.php?callback11=callajax11&callback=callajax
var url = url.split("?")[1];
var result = {},reg = /([^&=]+)=([^&]*)/g,m;
while(m = reg.exec(url)){
result[m[1]] = m[2];
}
return result;//Object {callback11: "callajax11", callback: "callajax"}
}
posted on 2013-04-26 10:56 liuyong1855 阅读(608) 评论(0) 收藏 举报
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