摘要:
LL CRT(int k, LL* a, LL* r) { LL n = 1, ans = 0; for (int i = 1; i <= k; i++) n = n * r[i]; for (int i = 1; i <= k; i++) { LL m = n / r[i], b, y; exgc 阅读全文
posted @ 2024-12-18 10:20
lyrrr
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摘要:
__int128 read(){ __int128 x=0,f=1; char ch=getchar(); while(!isdigit(ch)&&ch!='-')ch=getchar(); if(ch=='-')f=-1,ch=getchar(); while(isdigit(ch))x=x*10 阅读全文
posted @ 2024-12-18 00:19
lyrrr
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