09 2021 档案
摘要:n = input()for i in n: if ord("a") <= ord(i) <= ord("z"): print(chr(ord('z') - (ord(i) - ord('a'))),end = '') elif ord("A") <= ord(i) <= ord("Z"): pri
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摘要:stra = input("")x = 0z = 0y = 0for i in stra: if i == '(': x = x + 1 elif i == ')': if x >= 0: x = x - 1 else : print("配对不成功")if x != 0: print("配对不成功"
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摘要:x = input()for i in range(0,len(x)): if x[i] == ' ': print(' ',end="") elif x[i] in ['x','y','z']: print(chr(ord(x[i]) - 23),end="") else : print(chr(
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摘要:n = int(input())count = 0while (n != 1): lenth = list(str(n)) n = 0 for i in lenth: n = n + int(i)*int(i) count = count + 1 if count > 100: breakif n
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摘要:z = int(input()) z = abs(z)a = m + 10b = m - 10c = m * 10if (z>0): a = abs(a) b = abs(b) c = abs(c)else: a = -abs(a) b = -abs(b) c = -abs(c)print(z,a,
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摘要:x = 1.0b = 1.0N = float(input())for i in range(1,366): x = x + x*N*0.001for i in range(1,366): b = b - b*N*0.001y = x/bprint("努力的结果:{:.2f}, 放任的结果:{:.2
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摘要:n = int(input()) s = 1 for i in range(1,n+1): s = s * i print(s) 学号:37
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摘要:x = input("输入一个字符串:")print("使其逆序输出:"+x[::-1]) 学号:37
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摘要:x1 = float(input("输入一个数:"))x2 = round(x1,3)x_str = str(x2)print("格式化该数并保留三位小数:{}".format(x2)) 学号:37
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摘要:edge1 = float(input("输入边长1:"))edge2 = float(input("输入边长2:"))area = edge1*edge2area3= round(area,2)area_str = str(area3)print("由边长1与边长2组成的矩形的面积为:"+area
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摘要:通过一周的学习,我发现python比之前学的c++要简单很多,更加简洁方便,功能也更加强大十分有趣。
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摘要:print('\n * * * * *\n * *\n* @ @ *\n* *\n* @ *\n * *\n * *\n * * * *')学号3037
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